(5u^2-7u+4)+(-6u^2+2u+3)=

Solution for (5u^2-7u+4)+(-6u^2+2u+3)= equation:

(5u^2-7u+4)+(-6u^2+2u+3)=

We move all terms to the left:

(5u^2-7u+4)+(-6u^2+2u+3)-()=0

We add all the numbers together, and all the variables

(-6u^2+2u+3)+(5u^2-7u+4)=0

We get rid of parentheses

-6u^2+5u^2+2u-7u+3+4=0

We add all the numbers together, and all the variables

-1u^2-5u+7=0

a = -1; b = -5; c = +7;
Δ = b2-4ac
Δ = -52-4·(-1)·7
Δ = 53
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{53}}{2*-1}=\frac{5-\sqrt{53}}{-2}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{53}}{2*-1}=\frac{5+\sqrt{53}}{-2}
$